Implement the following operations of a stack using queues.
- push(x) -- Push element x onto stack.
- pop() -- Removes the element on top of the stack.
- top() -- Get the top element.
- empty() -- Return whether the stack is empty.
Example:
MyStack stack = new MyStack(); stack.push(1); stack.push(2); stack.top(); // returns 2 stack.pop(); // returns 2 stack.empty(); // returns false
Notes:
- You must use only standard operations of a queue -- which means only
push to back
,peek/pop from front
,size
, andis empty
operations are valid. - Depending on your language, queue may not be supported natively. You may simulate a queue by using a list or deque (double-ended queue), as long as you use only standard operations of a queue.
- You may assume that all operations are valid (for example, no pop or top operations will be called on an empty stack).
A:
就是简单的,每次都pop()出来,再放到最后去了
class MyStack {public:MyStack() {}void push(int x) {D.push_back(x);}int pop() {int n = D.size();for(int i =0;i<n-1;i++){int val = *D.begin();D.pop_front();D.push_back(val);}int res = *D.begin();D.pop_front();return res;}int top() {int val = 0;for(int i =0;i< D.size();i++){val = *D.begin();D.pop_front();D.push_back(val);}return val;}bool empty() {return D.empty();}private:deque<int> D;};/*** Your MyStack object will be instantiated and called as such:* MyStack* obj = new MyStack();* obj->push(x);* int param_2 = obj->pop();* int param_3 = obj->top();* bool param_4 = obj->empty();*/
Mistakes:
1: 第一遍的时候,理解成是用2个Stack来表示Queue了 太TMD搞笑(Diu Ren)了
2: 注意, D.begin() 返回的是iterator, 需要*
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