Q:
Given a m * n
matrix of distinct numbers, return all lucky numbers in the matrix in any order.
A lucky number is an element of the matrix such that it is the minimum element in its row and maximum in its column.
Example 1:
Input: matrix = [[3,7,8],[9,11,13],[15,16,17]]
Output: [15]
Explanation: 15 is the only lucky number since it is the minimum in its row and the maximum in its column
Example 2:
Input: matrix = [[1,10,4,2],[9,3,8,7],[15,16,17,12]]
Output: [12]
Explanation: 12 is the only lucky number since it is the minimum in its row and the maximum in its column.
Example 3:
Input: matrix = [[7,8],[1,2]]
Output: [7]
Constraints:
m == mat.length
n == mat[i].length
1 <= n, m <= 50
1 <= matrix[i][j] <= 10^5
.- All elements in the matrix are distinct.
A:
Given a m * n
matrix of distinct numbers, return all lucky numbers in the matrix in any order.
A lucky number is an element of the matrix such that it is the minimum element in its row and maximum in its column.
Example 1:
Input: matrix = [[3,7,8],[9,11,13],[15,16,17]] Output: [15] Explanation: 15 is the only lucky number since it is the minimum in its row and the maximum in its column
Example 2:
Input: matrix = [[1,10,4,2],[9,3,8,7],[15,16,17,12]] Output: [12] Explanation: 12 is the only lucky number since it is the minimum in its row and the maximum in its column.
Example 3:
Input: matrix = [[7,8],[1,2]] Output: [7]
Constraints:
m == mat.length
n == mat[i].length
1 <= n, m <= 50
1 <= matrix[i][j] <= 10^5
.- All elements in the matrix are distinct.
class Solution { public: vector<int> luckyNumbers (vector<vector<int>>& matrix) { vector<int> minRow ; for(auto & row : matrix){ minRow.push_back(*std::min_element(row.begin(), row.end())); } unordered_set<int> mySet; for(int j =0;j<matrix[0].size();++j){ int maxV = matrix[0][j]; for(int i =1;i<matrix.size();++i){ maxV = max(maxV, matrix[i][j]); } // cout<<maxV<<endl; mySet.insert(maxV); } vector<int> res; for(auto v : minRow){ if(mySet.find(v) != mySet.end()){ res.push_back(v); } } return res; } };
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