Q:
Given an integer n
, return the least number of perfect square numbers that sum to n
.
A perfect square is an integer that is the square of an integer; in other words, it is the product of some integer with itself. For example, 1
, 4
, 9
, and 16
are perfect squares while 3
and 11
are not.
Example 1:
Input: n = 12 Output: 3 Explanation: 12 = 4 + 4 + 4.
Example 2:
Input: n = 13 Output: 2 Explanation: 13 = 4 + 9.
Constraints:
1 <= n <= 104
A:
明显就是个 DP 问题
class Solution {
public:
int numSquares(int n) {
int seed = 1;
vector<int> squares;
while(seed * seed <=n){
squares.push_back(seed * seed);
seed++;
}
// DP
vector<int> minSquare(n+1,INT_MAX);
minSquare[0] = 0;
for(int i =1;i<=n;i++){
for(const auto c : squares){
if( i - c >=0){
minSquare[i] = min(minSquare[i], minSquare[i-c] +1);
}
}
}
return minSquare[n];
}
};
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