Given an integer n
, return the least number of perfect square numbers that sum to n
.
A perfect square is an integer that is the square of an integer; in other words, it is the product of some integer with itself. For example, 1
, 4
, 9
, and 16
are perfect squares while 3
and 11
are not.
Example 1:
Input: n = 12 Output: 3 Explanation: 12 = 4 + 4 + 4.
Example 2:
Input: n = 13 Output: 2 Explanation: 13 = 4 + 9.
Constraints:
1 <= n <= 104
A:
明显就是个 DP 问题
class Solution {
public:
int numSquares(int n) {
vector<int> V;
for (int i = 1; i * i <= n; i++) {
V.emplace_back(i * i);
}
vector<int> dp(n + 1, INT_MAX);
dp[0] = 0;
for (int val = 1; val <= n; val++) {
for (auto square : V) {
if (val - square >= 0) {
if (dp[val - square] != INT_MAX) {
dp[val] = min(dp[val], 1 + dp[val - square]);
}
}
}
}
return dp[n];
}
};
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