Given a 2D integer matrix M representing the gray scale of an image, you need to design a smoother to make the gray scale of each cell becomes the average gray scale (rounding down) of all the 8 surrounding cells and itself. If a cell has less than 8 surrounding cells, then use as many as you can.
Example 1:
Input: [[1,1,1], [1,0,1], [1,1,1]] Output: [[0, 0, 0], [0, 0, 0], [0, 0, 0]] Explanation: For the point (0,0), (0,2), (2,0), (2,2): floor(3/4) = floor(0.75) = 0 For the point (0,1), (1,0), (1,2), (2,1): floor(5/6) = floor(0.83333333) = 0 For the point (1,1): floor(8/9) = floor(0.88888889) = 0
Note:
- The value in the given matrix is in the range of [0, 255].
- The length and width of the given matrix are in the range of [1, 150].
A:
class Solution { public: vector<vector<int>> imageSmoother(vector<vector<int>>& M) { int m = M.size(), n = M[0].size(); vector<vector<int> > res(m, vector<int>(n,0)); for(int i =0;i<m;++i) for(int j =0;j<n;++j) { int c = 0, sum =0; for(int a=-1;a<=1;++a) for(int b = -1;b<=1;++b) { if(i+a>=0 && i+a<m && j+b >=0 && j+b <n){ ++c; sum += M[i+a][j+b]; } } res[i][j] = sum/c; } return res; } };
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