Friday, March 6, 2020

559. Maximum Depth of N-ary Tree

Given a n-ary tree, find its maximum depth.
The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.
Nary-Tree input serialization is represented in their level order traversal, each group of children is separated by the null value (See examples).

Example 1:
Input: root = [1,null,3,2,4,null,5,6]
Output: 3
Example 2:
Input: root = [1,null,2,3,4,5,null,null,6,7,null,8,null,9,10,null,null,11,null,12,null,13,null,null,14]
Output: 5

Constraints:
  • The depth of the n-ary tree is less than or equal to 1000.
  • The total number of nodes is between [0, 10^4].

A:

/*
// Definition for a Node.
class Node {
public:
    int val;
    vector<Node*> children;

    Node() {}

    Node(int _val) {
        val = _val;
    }

    Node(int _val, vector<Node*> _children) {
        val = _val;
        children = _children;
    }
};
*/
class Solution {
public:
    int maxDepth(Node* root) {
        if(not root)
            return 0;
        int dChild = 0;
        for(auto it = root->children.cbegin(); it!= root->children.cend(); ++it)
        {
            int d = maxDepth(*it);
            dChild = max(dChild, d);
        }
        return 1 + dChild;
    }
};



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