Given a n-ary tree, find its maximum depth.
The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.
Nary-Tree input serialization is represented in their level order traversal, each group of children is separated by the null value (See examples).
Example 1:
Input: root = [1,null,3,2,4,null,5,6] Output: 3
Example 2:
Input: root = [1,null,2,3,4,5,null,null,6,7,null,8,null,9,10,null,null,11,null,12,null,13,null,null,14] Output: 5
Constraints:
- The depth of the n-ary tree is less than or equal to
1000
. - The total number of nodes is between
[0, 10^4]
.
A:
/* // Definition for a Node. class Node { public: int val; vector<Node*> children; Node() {} Node(int _val) { val = _val; } Node(int _val, vector<Node*> _children) { val = _val; children = _children; } }; */ class Solution { public: int maxDepth(Node* root) { if(not root) return 0; int dChild = 0; for(auto it = root->children.cbegin(); it!= root->children.cend(); ++it) { int d = maxDepth(*it); dChild = max(dChild, d); } return 1 + dChild; } };
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