A rectangle is represented as a list [x1, y1, x2, y2]
, where (x1, y1)
are the coordinates of its bottom-left corner, and (x2, y2)
are the coordinates of its top-right corner.
Two rectangles overlap if the area of their intersection is positive. To be clear, two rectangles that only touch at the corner or edges do not overlap.
Given two (axis-aligned) rectangles, return whether they overlap.
Example 1:
Input: rec1 = [0,0,2,2], rec2 = [1,1,3,3] Output: true
Example 2:
Input: rec1 = [0,0,1,1], rec2 = [1,0,2,1] Output: false
Notes:
- Both rectangles
rec1
andrec2
are lists of 4 integers. - All coordinates in rectangles will be between
-10^9
and10^9
.
A:
class Solution { public: bool isRectangleOverlap(vector<int>& rec1, vector<int>& rec2) { if(rec1[2] <= rec2[0] || rec2[2] <= rec1[0] ) return false; if(rec1[3] <= rec2[1] || rec2[3] <= rec1[1]) return false; return true; } };
比较操蛋的是, 2个点是bottom-left and top right.
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