Given the root
of a binary tree, return its maximum depth.
A binary tree's maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.
Example 1:

Input: root = [3,9,20,null,null,15,7] Output: 3
Example 2:
Input: root = [1,null,2] Output: 2
Constraints:
- The number of nodes in the tree is in the range
[0, 104]
. -100 <= Node.val <= 100
A:
/*** Definition for a binary tree node.* struct TreeNode {* int val;* TreeNode *left;* TreeNode *right;* TreeNode() : val(0), left(nullptr), right(nullptr) {}* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}* };*/class Solution {public:int maxDepth(TreeNode* root) {return !root? 0:1+max(maxDepth(root->left), maxDepth( root->right));}};
Learned:
注意,以前的一个错误。 就是,null也可以作为参数传递给方法。
也就是说,上面的代码, 当root.left == null 的时候,依然正确。
No comments:
Post a Comment