There are a row of n houses, each house can be painted with one of the three colors: red, blue or green. The cost of painting each house with a certain color is different. You have to paint all the houses such that no two adjacent houses have the same color.
The cost of painting each house with a certain color is represented by a n x 3
cost matrix. For example, costs[0][0]
is the cost of painting house 0 with color red; costs[1][2]
is the cost of painting house 1 with color green, and so on... Find the minimum cost to paint all houses.
Note:
All costs are positive integers.
Example:
Input: [[17,2,17],[16,16,5],[14,3,19]] Output: 10 Explanation: Paint house 0 into blue, paint house 1 into green, paint house 2 into blue. Minimum cost: 2 + 5 + 3 = 10.A:
DP
class Solution { public: int minCost(vector<vector<int>>& costs) { int n = costs.size(); if(n==0) return 0; for(int i =1;i<n;i++){ costs[i][0] += min( costs[i-1][1], costs[i-1][2]); costs[i][1] += min( costs[i-1][0], costs[i-1][2]); costs[i][2] += min( costs[i-1][0], costs[i-1][1]); } return min(costs[n-1][0], min(costs[n-1][1], costs[n-1][2] )); } };
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