Given a fixed length array arr
of integers, duplicate each occurrence of zero, shifting the remaining elements to the right.
Note that elements beyond the length of the original array are not written.
Do the above modifications to the input array in place, do not return anything from your function.
Example 1:
Input: [1,0,2,3,0,4,5,0] Output: null Explanation: After calling your function, the input array is modified to: [1,0,0,2,3,0,0,4]
Example 2:
Input: [1,2,3] Output: null Explanation: After calling your function, the input array is modified to: [1,2,3]
Note:
1 <= arr.length <= 10000
0 <= arr[i] <= 9
A:
class Solution { public: void duplicateZeros(vector<int>& arr) { int c0 = 0; int n = arr.size(); for(auto val : arr){ if(val == 0) ++c0; } int endIndex = n+c0-1; for(int i = n-1;i>=0;i--){ int val = arr[i]; if(val ==0){ if(endIndex <n){ arr[endIndex] =0; } endIndex--; } if(endIndex <n){ arr[endIndex] = val; } endIndex --; } } };
No comments:
Post a Comment